4x+2[4-2(x+2)]=2x-1

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Solution for 4x+2[4-2(x+2)]=2x-1 equation: 


Simplifying
4x + 2[4 + -2(x + 2)] = 2x + -1

Reorder the terms:
4x + 2[4 + -2(2 + x)] = 2x + -1
4x + 2[4 + (2 * -2 + x * -2)] = 2x + -1
4x + 2[4 + (-4 + -2x)] = 2x + -1

Combine like terms: 4 + -4 = 0
4x + 2[0 + -2x] = 2x + -1
4x + 2[-2x] = 2x + -1

Remove brackets around [-2x]
4x + 2 * -2x = 2x + -1

Multiply 2 * -2
4x + -4x = 2x + -1

Combine like terms: 4x + -4x = 0
0 = 2x + -1

Reorder the terms:
0 = -1 + 2x

Solving
0 = -1 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
0 + -2x = -1 + 2x + -2x
Remove the zero:
-2x = -1 + 2x + -2x

Combine like terms: 2x + -2x = 0
-2x = -1 + 0
-2x = -1

Divide each side by '-2'.
x = 0.5

Simplifying
x = 0.5

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